Experiment 1

Specific Heat of Copper 

Physics Dept.
Lab Contents

Objective: 

  To determine the specific heat of copper.

Required Reading: 

  Appendix on errors and uncertainties

Introduction

Heat is energy that flows from one body to another because of a temperature difference between them.  The specific heat of a substance is a measure of the amount of heat (energy) needed to raise the temperature of a unit mass of the substance by 1 °C. It is sometimes called specific heat capacity. Therefore, if heat Q leads to a temperature change DT of an amount of mass m, the specific heat, c, is

c = 

  Q  
m DT

 =

       heat energy supplied        
mass  ´ temperature change

(1)

For example, water has a specific heat of (4.184 ± 0.002) ´ 103 J/kg×°C. In terms of the non-SI heat unit of calorie, the specific heat of water is 1 calorie/g×°C , which allows the specific heats of other substances to be easily compared to that of water. The specific heat of water is unusually large compared to most other substances, which is a subject of recent research interest.

The calorimeter (a container used in measuring quantities of heat exchange) is made of aluminum, whose specific heat can be found in the appendix on constants & conversions

Theory

The measurement of heat transfers is accomplished by "the method of mixtures".  By this method, two bodies initially at different temperatures are placed in thermal contact in a calorimeter. Heat is transferred between the bodies until some intermediate equilibrium temperature is reached.  Experimentally this is done by dropping a heated substance (in this experiment it is copper) into cool water and allowing thermal equilibrium to be reached. Thus the heat transferred, Q, is given by:

Q =  

heat energy lost
by the substance

=

heat energy gained
by the water

+

heat energy gained by the
container holding the water

(2)

This assumes that no heat is exchanged with the surroundings (i.e. the air in the room), which is an unrealistic  assumption  In this experiment, if the water and the container are initially as much below room temperature as the final equilibrium temperature is above it, then heat lost to the room will approximately equal heat absorbed from it. This will minimize the error due to the idealistic assumption. 

Thus, for this experiment, where copper is dropped into water in an aluminum calorimeter, Equations (1) and (2) will yield:

QCu

Qwater + Qcontainer

(3)

 

(mc DT)Cu

(mc DT)water + (mc DT)Al

(4)

 

=  

[mwatercwater + mAlcAl] DTwater

(5)

where the last line follows because the temperature of the water and of the calorimeter change by the same amount. Note that DT is the absolute value of change in temperature of the substance (e.g. for copper DT = Tinitial of copper - Tfinal of copper ). Also, note that everything in Equation (4) is either given or can be measured, except for the specific heat of copper, c, which can then be calculated from this equation.